Find the missing angle measures of 2 and 3. Plz help

For #2.

All of the angles are measured x. They are all the same so they must equal each other.

So,

x = 60°

Because 60 + 60 + 60 = 180° and 60° = 60°.

For #3

Three angles should add up to 180 since it is the total angle.

n + 1/2n + 1/2n = 180

Solve for n:

n + n = 180

2n = 180

n = 180 ÷ 2

n = 90°

1/2 n

1/2 (90) = 45°

1/2 n = 45°

2) x=60°

they have labelled all 3 x, which means that it's an equilateral triangle, all angles are equal, and all sides are equal

3)

this is an isosceles triangle, since 2 of the sides are equal 1/2 (n).

so n+n=180

this triangle has a right angle, angle ZXY (X)

so n= 90

90+90=180

90+(1/2*(90)*2)=180

90+(45*2)=180

∠ZXY=90°

∠YZX and ∠ZYX = 45°

hello i am doing good for you that it's summer in your country or state ; )

btw in my country we just have sun and rain as (because i live in the caribbean lol)

also, thx a lot for the points : )

answer: 5

step-by-step explanation:

since, the range is the difference between the lowest and highest values of the given sample space.

and, here the sample space = { 3, 1, 0, 4, 1, 4, 2, 3, 0, 5, 0, 1, 1, 2, 0, 4, 1,4, 4 ,2 ,3 ,2 ,0 ,1 ,4 }

here, the highest value of the given sample = 5

and, the lowest value = 0

therefore, the range of the sample space = 5 - 0 = 5