Line jk passes through points j(–4, –5) and k(–6, 3). if the equation of the line is written in slope-intercept form, y = mx + b, what is the value of b?
–21
–4
11
27

(-4,-5)(-6,3)
slope(m) = (3 - (-5) / (-6 - (-4)
slope(m) = (3 + 5) / (-6 + 4)
slope(m) = 8/-2 = -4

y = mx + b
slope(m) = -4
u can use either of ur points...I will use (-6,3)
3 = -4(-6) + b
3 = 24 + b
3 - 24 = b
- 21 = b <== here ya go

I'll do the first one for you. it isn't very hard at all.on number one, you have (50 × 3), which equals 150, and (3 × 3), which equals 9. after you establish that, you add 150 and 9 together. so, (150 + 9) equals 159.this means that 53 × 3 = 159.