Let f={(-2,4),(-1,2)(0,0)(1,-2),(2,5)}. let g ={(-33),(-1,1),(0,-3)(1,-4)(3,-6)}. What is g(f(2))?

g(f(2)) does not exist if

g={(-3,3),(-1,1),(0,-3),(1,-4),(3,-6)} and f={(-2,4),(-1,2),(0,0),(1,-2),(2,5)}.

Step-by-step explanation:

Hi. Welcome to .

When finding g(f(2)), you must compute f(2) first.

Looking at f={(-2,4),(-1,2),(0,0),(1,-2),(2,5)}, we see that the ordered pair (2,5) is contained within the set defined as the set f. This means f(2)=5.

So now we have g(f(2))=g(5).

We now need to look at our set named g, g={(-3,3),(-1,1),(0,-3),(1,-4),(3,-6)}. We see the the no ordered pair looks like (5,something). The only conclusion is that g(f(2)) does not exist.

well there are two answers for that.

1: you need 120 ones then that will equal up to 120.

2: you could also do one 100 and 2 tens.

those are the answers that i have thought of.