Suppose a triangle has two sides of length 33 and 37, and that the angle
between these two sides is 120°. Which equation should you solve to find the
length of the third side of the triangle?
O A. c= 33 + 37 - 2(33)(37)cos120°
O B. sin83 = sin37
OC. 2 = 332 + 372 – 2(33)(37)sin120°
O D. 22 = 332 + 372 – 2(33)(37)cos120°

3. parallelogram

step-by-step explanation:

we turn each of our sides into direction vectors

ab=b-a=(3 - 7, 1 - 0) = (-4, 1)

bc=c-b=(1,6)

cd=d-c=(4,-1)

da=a-d=(-1,-6)

we see how the opposite sides have negated direction vectors; this is characteristic of a parallelogram.   we have congruent sides ab=cd and bc=da with unequal lengths because 1^2+6^2 is different from (-4)^2+1^2.   so it's not a square or a rhombus.  

we check the dot product of direction vectors of adjacent sides.   we have

ab dot bc = -4(1) + 1(6) = 2

that's not zero so the sides are not perpendicular.   we've ruled out rectangle.

the direction vectors indicate two pairs of congruent parallel sides, so we choose parallelogram over trapezoid.

x = -4

step-by-step explanation:

- 20 - 4(x + 3) = 4x

=> -20 - 4x - 12 = 4x

=> - 32 -4x = 4x

=> -32 = 4x + 4x

=> - 32 = 8x

=> -32/8 = x

=> -4 = x

where is the diagram? shown below where? ?

step-by-step explanation:

b. f(x) = –√x + 3this is the correct answer