Given a test statistic of t=2.315 of a left tailed test with n=8

Null hypothesis:

Alternative hypothesis:

The sample size on this case is n=8, then the degrees of freedom are given by:

The statistic is given by:

For this case the value of the statistic is given

Since we are using a bilateral test the p value would be given by:

And we can use the following excel code to find it:

"=2*(1-T.DIST(2.315;7;TRUE))"

Since the p value is higher than the significance level given we FAIL to reject the null hypothesis. And the best conclusion would be:

0.05<P-value <0.10, fail to reject the null hypothesis

Step-by-step explanation:

Assuming this complete question :"Given a test statistic of t=2.315 of a left-tailed test with n=8, use a 0.05 significance level to test a claim that the mean of a given population is equal to 110.

Find the range of values for the P-value and state the initial conclusion 1 point) 0.05<P-value <0.10; reject the null hypothesis

0.05<P-value <0.10, fail to reject the null hypothesis

0.025 < P-value <0.05; reject the null hypothesis

0.025< P-value<0.05; fail to reject the null hypothesis "

For this case they want to test if the population mean is 110 or no, the systemof hypothesis are:

Null hypothesis:

Alternative hypothesis:

The sample size on this case is n=8, then the degrees of freedom are given by:

The statistic is given by:

For this case the value of the statistic is given

Since we are using a bilateral test the p value would be given by:

And we can use the following excel code to find it:

"=2*(1-T.DIST(2.315;7;TRUE))"

Since the p value is higher than the significance level given we FAIL to reject the null hypothesis. And the best conclusion would be:

0.05<P-value <0.10, fail to reject the null hypothesis

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