Each day, a weather forecaster predicts whether or not it will rain. For 80% of rainy days, she correctly predicts that it will rain. For 90% of non-rainy days, she correctly predicts that it will not rain. Suppose that 10% of days are rainy and 90% are non-rainy.
What proportion of the forecasts are correct?

Our required proportion of the forecasts are correct is 89%.

Step-by-step explanation:

Since we have given that

Percentage of rainy days she correctly predicts that it will rain = 80%

Percentage of non rainy days, she correctly predicts that it will not rain = 90%

Percentage of rainy days = 10%

Percentage of non rainy  days = 90%

So, Probability of forecasts are correct is given by

P(rainy day).P(correctly predicted) + P(non rainy day) .P(correctly predicted)

Hence, our required proportion of the forecasts are correct is 89%.

i believe it is c.y = 9x

rise over run. 9 units up over 1 unit right or 9/1

the inequality is:

250c+180g≥950

step-by-step explanation:

let c denotes the number of days in a week   miyoko worked as a cryptographer.

and g denotes the number of days in a week she works as a geologist.

now we are given that she earns $250 for every day she works as a cryptographer,and earns $180 for every day she works as a geologist.

now miyoko's goal is to earn more than $950 this week.

hence, the inequality could be represented as:

250c+180g≥950