Find the solution to the following linear, homogeneous recurrence with constant coefficients:
an=8an−1−20an−2 for n≥2an=8an−1−20an−2 for n≥2 with initial conditions a0=0,a1=−12a0=0,a1=−12. The solution is of the form:

an=(α+iβ)(r+is)n+(α−iβ)(r−is)nan=(α +iβ)(r+is)n+(α−iβ)(r−is)n

For suitable real constants α,β,r, sα,β,r, s.

Find these constants and enter their values:

α =

β =

r =

s =

sα =

6^2 or 36

step-by-step explanation:

6000n

6×1000n

6×10^3 n

so we need 6n need to be a perfect cube

so n has to be 6^2 so that 6n is 6^3

what i'm saying is if you let n be 6^2 you have 6^3×10^3 or 60^3 which is a perfect cube

its kinda hard to answer this when we dont have all the information that we need.

the correct answer option is d. la = πrs.

step-by-step explanation:

we know that for a right cone, the lateral surface area is given by:

lateral area of right cone =

here the value under the square root is equal to slant height so replacing this value by in the formula to get:

lateral area of right cone =

therefore, the correct answer option is d.

if y=4x then you will substitute 4x in for y in the second equation.

8x + 4x = 18 combine like terms

12x = 18 divide by 12 on both sides

x = 18/12 or 3/2

now replace x in the first equation with 3/2 to get

y = 4 3/2

y = 6

the answer is a

(3/2,6)

hope that .

brainliest is always apprectiated