What is the minimum and maximum of x²-2x-5?

Minimum: (1,4) Maximum: None

Step-by-step explanation:

The vertex 1,4 is the minimum because the equation opens upwards. You can simply graph the equation at desmos.com calculator

There is no maximum because the equation continues upward forever

You can also look up symbolab's maximum/minimum calculators.

b

step-by-step explanation:

answer: (c) m∠qpo + (2x + 16)° = 180°

step-by-step explanation:

the opposite angles of a quadrilateral are supplementary.

so, ∠o + ∠q = 180°   and   ∠p + ∠r = 180°

since ∠r = 2x + 16°, we can use substitution as follows:

∠p + ∠r = 180°

∠p + (2x + 16)° = 180°