Solve for x in the equation x squared minus 12 x + 36 = 90. x = 6 plus-or-minus 3 StartRoot 10 EndRoot x = 6 plus-or-minus 2 StartRoot 7 EndRoot x = 12 plus-or-minus 3 StartRoot 22 EndRoot x = 12 plus-or-minus 3 StartRoot 10 EndRoot

x = 6 plus-or-minus 3 StartRoot 10

Step-by-step explanation:

The given quadratic equation is expressed as

x² - 12x + 36 = 90

Rearranging the equation so that it takes the the standard form of

ax² + bx + c, it becomes

x² - 12x + 36 - 90 = 0

x² - 12x - 54 = 0

The general formula for solving quadratic equations is expressed as

x = [- b ± √(b² - 4ac)]/2a

From the equation given,

a = 1

b = - 12

c = - 54

Therefore,

x = [- - 12 ± √(- 12² - 4 × 1 × - 54)]/2 × 1

x = [12 ± √(144 + 216)]/2

x = [12 ± √360]/2

x = (12 ± 6√10)/2

x = 6 + 3√10

step-by-step explanation:

this is not a question

sorry but i cant draw that