If f(x) is a third degree polynomial function, how many distinct complex roots are possible?
0or 2
0, 1, 2, or 3
1 or 2
1, 2, or 3

Answer A

Step-by-step explanation:

if coefficients are reals, then 0 or 2 complex roots (an even number) for if a is a root its conjuate is also a root.

0 or 2

Step-by-step explanation:

If a polynomial has complex roots, they occur in conjugate pairs.

Since degree is 3, there can be at max 1 pair (which is 2 complex no.sl

Or roots can be all real

f(x) is going down by 4

step-by-step explanation:

(its either that or its going left by 4)

i dont know sorry

step-by-step explanation: