PLZZ HELP TRIG/GEO

Kayson is looking at two buildings, building A and building B, at an angle of elevation of 59°. Building A is 40 feet away, and building B is 60 feet away. Which building is taller and by approximately how many feet?

Building A; it is around 66.57 feet taller than building B
Building A; it is around 33.29 feet taller than building B
Building B; it is around 66.57 feet taller than building A
Building B; it is around 33.29 feet taller than building A

Option D - Building B; it is around 33.29 feet taller than building A

Step-by-step explanation:

Step 1 :

Let x be the height of building A and y be the length of building B

Angle of elevation is 59°

We can consider this as a right angle triangle , opposite side as x and adjacent side as 40 (As building A is 40 feet away  )

Therefore tan 59 = x/40 = > x = 40* tan 59 = 40 * 1.664 = 66.56

Step 2:

Similarly with respect to building B, we have a right angle triangle with opposite side as y and adjacent side as 60(as building B is 60 feet away)

So here tan 59 = y/60 => y = 60 * tan 59 = 60 * 1.664 = 99.84

Step 3:

Height of building A is 66.56 feet

Height of building B is 99.84 feet

Hence building B is taller than building A by (99.84-66.56) = 33.28 feet

hi,

6x times 4 is 24x and 5 times 4 is 20, so the answer is 24x+20.

hope this and for a little humor i am groot.

solution:

the given function is ,

      =

the three roots of this quadratic function is , 0 ,8 and 10.all the roots are real and rational.

if a quadratic equation is of the form ,

sum of the roots = a + b +c= 0+8+10=18=  

product of roots taken two at a time = a b + b c+ c a = 0+80+0=80 =  

product of roots = a b c = 0=  

there are 11 doors in a hall starting from 0 to 11.the entry in the hall is permitted through gate number 0 and exit is allowed through only gate number 8 and 10.so, three roots(0,8,10) of quadratic function is given by entry and exit route of this hall.