Thickness measurements of a coating process aremade to the nearest hundredth of amillimeter. The thickness measurementsare uniformly distributed with values 0.15, 0.16, 0.17,0.18, and 0.19. Determine the mean and variance of the coatingthickness for this process.

Mean= 0.17 millimetre and

variance =  2×10⁻⁴ square millimetre

Step-by-step explanation:

Mean: The average of all numbers is also known as mean.

Standard deviation: It is quantity which shows that the element of data how much differ from the mean of the distribution.

Given data

0.15,0.16,0.17,0.18 and 0.19.

This is a discrete uniform distribution.

Uniform distribution: All element of uniform distribution is likely.

The elements discrete uniform distribution can be written as [a,b]

The mean of uniform distribution is =

And variance =

Here , a= 15 and b= 19

Mean= =0.17

Variance=

              = 2×10⁻⁴

goog may have it for you