Which of these expressions CANNOT be simplified by combining like terms?

CLEAR CHECK

5ab3+7−3a2b2+a3b−10

5ab3+3a2b2+a3b−10

5ab3+2b(3ab2)+a3b−10

5a3b3+3a2b2+a3b3−10ab

2.83941151 would be the answer you're looking for! : )

∠1≅∠2 by the alternate exterior angles theorem.

step-by-step explanation:

given, a ∥ b and ∠1 ≅ ∠3 .we have to prove that e ∥ f

we know that ∠1≅∠3 and that a || b because they are given. we see that by the alternate exterior angles theorem. therefore, ∠2≅∠3 by the transitive property. so, we can conclude that e || f by the converse alternate exterior angles theorem.

we have to fill the missing statement.

transitivity property states that if a = b and b = c, then a = c.

now, given ∠1≅∠3 and by transitivity property ∠2≅∠3 .

hence, to apply transitivity property one angle must be common which is not in result after applying this property which is ∠1.

the only options in which ∠1 is present are ∠1 and ∠2, ∠1 and ∠4

∠1 and ∠4 is not possible ∵ after applying transitivity we didn't get ∠4.

hence, the missing statement is ∠1≅∠2.

so, ∠1≅∠2 by the alternate exterior angles theorem.

step-by-step explanation:

options

4 candies

step-by-step explanation:

7 x 28 = 196

200 - 196 = 4 candies remaining.