Consider the point (8 2) and the line L given by the equation y = 4x - 6 what is the equation of the line in slope intercept form passing through point P and perpendicular to line L

y = -x/4 + 4 (slope intercept form)

Step-by-step explanation:

From Equation of the line L, y=4x - 6 and comparing with the general equation of line, y=mx+c, we have,

m1 = 4

For perpendicularity:

m1m2 = -1

m2 = -1/4

Hence, the equation of the line passing through (8,2) and perpendicular to L is

y - y1 = m2(x-x1)

y - 2 = -1/4(x-8)

y-2 = -x/4 + 2

y = -x/4+2+2

y = -x/4 + 4 (slope intercept form)

where slope, m2= -1/4, c = 4

b. would be the answer : )

step-by-step explanation:

step 1: add -16x to both sides.

16x−4y+−16x=64+−16x  

−4y=−16x+64

step 2: divide both sides by -4.

−4y /-4 = -16x + 64/-4

answer:   y=4x−16

hope i'm right

$2416.6

step-by-step explanation:

per hour = $ 25

total work time = 35

commission = 15%

total she has to make = $ 4,500

let she sold x dollar products

so her commission will be 15 % of x

now

total = weekly basic pay + commission

4500= (25*35) + 15 % of x

4500=875 + * x

4500-875 =   * x

3625= * x

multiplying wwith 100 on both sides gives

36250 = 15 x

now

x =  

x= $2416.6