Subtract. (2/9v)−(−1/3v+5/9) A. 5/9v+5/9 B. 1/9v+5/9 C. 5/9v−1/3 D. 5/9v−5/9

D. (5/9v - 5/9)

Step-by-step explanation:

(2/9v)- (-1/3v+ 5/9)

Since it is subtraction, we have to change the sign of the second expression that is after the (-) sign.

= (2/9v + 1/3v - 5/9)

Since we have different denominators, we have to take LCM of 3 and 9 as 3, so the expression becomes,

= (2/9v + 3/9v - 5/9)

= (5/9v - 5/9)

      2

  2 is to go somewhat to the top right of a because it is squared    

v= a h/3

step-by-step explanation:

i'm not sure how to show the work for this

answer : c and d or 4(29 + 6)

4(29) + 4(6)