Consider a water pipe that branches into two smaller pipes. If the flow of water is 10 L/min in the main pipe and 4 L/min in one of the branches, how much water per minute flows in the other branch?

The water flows 6 liters per minute in the other branch of pipe.

Step-by-step explanation:

Given,

Flow of water in main pipe = 10L/min

Flow of water in one branch = 4L/min

Flow of water in other branch = x

Flow of water in main pipe = Flow in one branch + Flow in other branch

The water flows 6 liters per minute in the other branch of pipe.

intensity of the vector is v= √37 ≈ 6.08 units and make angle ∡α ≈ 9.46° with east direction

step-by-step explanation:

required vector is consists of the two componentsvx= 2+4=6 units   and vy= 1 unit and vx ⊥ vywe will use pythagorian theorem to find intensity of the vector vv∧2 = vx∧2 + vy∧2 => v = √vx∧2 + vy∧2 = √6∧2 + 1∧2 = √36+1 = √37 ≈ 6.08 unitsthe angle ∡α between vector and east direction we wil find with tanαtanα = 1/6 => α = arc tanα = arc 1/6 => α ≈ 9.46°

hope this