I’m really stuck on this circle theorems question, can someone help please

Step-by-step explanation:

O is the center of the circle.  So OD, OC, and OB are all radii of the circle, and therefore congruent.

That means that ΔDCO and ΔCBO are isosceles triangles.  The base angles of isosceles triangles are congruent.  So ∠DCO = x.

ADP and ABQ are tangent to the circle.  Therefore, they are perpendicular to OD and OB.

Since ∠ABO = 90°, ∠CBO = 90° − 2x.  Which means ∠OCB = 90° − 2x.

∠BCD is the sum of ∠DCO and ∠OCB:

∠BCD = x + 90° − 2x

∠BCD = 90° − x

Angles of a triangle add up to 180°.  So:

∠DOC = 180° − x − x = 180° − 2x

∠BOC = 180° − (90° − 2x) − (90° − 2x) = 4x

Central angles add up to 360°.  So ∠DOB is:

∠DOB = 360° − (180° − 2x) − (4x)

∠DOB = 180° − 2x

The interior angles of kite ADOB add up to 360°.

360° = 90° + 90° + (180° − 2x) + y

360° = 360° − 2x + y

y = 2x

idkit the do u know da way and ligma consumed ninja

step-by-step explanation:

5x + 3y = - 4

step-by-step explanation:

the equation of a line in standard form is

ax + by = c ( a is a positive integer and b, c are integers )

express the line first of all in slope- intercept form

y = mx + c ( m is the slope and c the y-intercept )

to calculate m use the gradient formula

m = ( y₂ - y₁ ) / ( x₂ - x₁ )

with (x₁, y₁ ) = (7, - 3) and (x₂, y₂ ) = (4, - 8)

m = = -

y = - x + c ← is the partial equation

to find c substitute either of the 2 points into the partial equation

using (4, - 8 ), then

- 8 = - + c ⇒ c = -

y = - x - ← in slope-intercept form

multiply all terms by 3 to eliminate the fractions

3y = - 5x - 4 ( add 5x to both sides )

5x + 3y = - 4 ← in standard form