Assume that when with smartphones are randomly selected, 46% use them in meetings or classes. If 12 adult smartphone users are randomly selected, find the probability that fewer than 3 of them use their smartphones in meetings or classes.

The probability that fewer than 3 of them use their smartphones in meetings or classes is 0.03634

Step-by-step explanation:

Apply binomial probability formula which is written as;

where P=46% =0.46, n=12

For this case where you find the probability that fewer than 3 of them use their smartphones in meeting or classes, x=2,1,0

Evaluating binomial probability at x=2 will be;

P(X=2)=0.02944

Evaluate binomial probability at x=1

P(X=1)= 0.006284

Evaluate binomial probability at x=0

P(X=0)=0.0006148

Now for P(X<3)=P(X=2)+P(X=1)+P(X=10) =0.02944+0.006284+0.0006148

=0.0363388

=0.03634 (in 4 significant figures)

c) yes, because of asa or aas

answer:   expression= p+p*d%

price reduction + sale price = $625

sale price: $p+$p*d%

where d% is the percentage of discount

step-by-step explanation:

original price = p

price went down by $150 price reduction $p*d%

sale price= $ 475

therefore the price before sale is: $625

and the expression that shows the price before sale is: p+p*d%