Assume that when with smartphones are randomly selected, 46% use them in meetings or classes. If 12 adult smartphone users are randomly selected, find the probability that fewer than 3 of them use their smartphones in meetings or classes.

3.6%

Step-by-step explanation:

There is a 46% chance for someone to use the smartphone(A) and 54% that they didn't use the smartphone(B). The question of asking the probability that fewer than 3 of them use their smartphones. The calculation will be:

12C0 * A^12 * B^0       +    12C1 * A^11 * B^1       + 12C2 * A^10 * B^2

12C0 * 54%^12 * 46%^0       + 12C1 * 54%^11 * 46%^1      + 12C2 * 54%^10 * 46%^2       =

0.0006147876262 + 0.006284495734 + 0.02944402631

0.03634330967 = 3.6%

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step-by-step explanation:

answer: 204

step-by-step explanation:

we are told that the revenue is

x⋅(4080−10x)=−10x^2+4080x

this is a quadratic function, so to maximize it we should find the x-value of its vertex. recall that the x-value of the vertex of the parabola ax^2+bx+c is given by the formula −b/2a.

so in this case, we have a=−10 and b=4080, so the x-value of the vertex is

−b/2a= −(4080)/2(−10)=204