Find an equation of the line passing through the point (5,4) and perpendicular to the line 2x+y=3

Step-by-step explanation:

Given equation of line is:

Equating it with we find:

Let the slope of required line be

Required line is parallel to the given line.

Required line passes through (5, 4) and has a slope

Equation of line in slope point form is given as:

Hence, x -2y + 3=0 is the required equation of line.

  x -2y = -3

Step-by-step explanation:

The line perpendicular to

  ax +by = c

through point (h, k) can be written as ...

  b(x -h) -a(y -k) = 0 . . . . . swap x and y coefficients, negate one of them.

Putting this in standard form gives ...

  bx -ay = bh -ak

For a=2, b=1, and (h, k) = (5, 4), this is ...

  x -2y = 5 -2(4) = -3

  x -2y = -3

_____

The graph shows the two lines and the point.

a

step-by-step explanation:

when a number is between two straight lines it means the absolute value.

to find absolute value you need to know how many numbers is that number away from 0.

when finding absolute value the number will always come out positive

so absolute value of -3 is 3

absolute value of 3/2 is 3/2

absolute value of -2 is 2

absolute value of 3.5 is 3.5

absolute value of -1 is 1

now put these numbers in order:

a)   |-1|, |3/2|, |-2|, |-3|, |3.5|