If M is a two digit number and N is obtained by reversing M, if M+N =132, how many values can M have?

7

Step-by-step explanation:

Let M be a two digit number with x in the tens position and y in units:

M = 10x + y

Then N will have y in the tens position and x in units:

N = 10y + x

M+N = 10x + y + 10 + x = 132

11x + 11y = 132

11(x + y) = 132

x + y = 12

x and y are single digit whole numbers. Possible combinations are:

x = 3 y = 9

x = 4 y = 8

x = 5 y = 7

x = 6 y = 6

x = 7 y = 5

x = 8 y = 4

x = 9 y = 3

Values of M can be:

39, 48, 57, 66, 75, 84, 93

Which are 7

i believe the answer is c.

i believe the answer is 323 ft

step-by-step explanation: