You may remember that the perimeter of a rectangle is P=2(W+L) where W is the width and L is the length. Suppose that the perimeter of a rectangle is 44 feet, and the length is 12 feet more than the width. Find the width of the rectangle, in feet.

The width of the rectangle is 5 feet.

Step-by-step explanation:

Let w represent the width of the rectangle.

The formula for determining the perimeter of a rectangle is expressed as

Perimeter = 2(W + L)

where W is the width and L is the length.

If the length of the rectangle is 12 feet more than the width, the expression would be

L = W + 12

Suppose that the perimeter of a rectangle is 44 feet, it means that

2(W + L) = 44

Dividing both sides of the equation by 2, it becomes

W + L = 22 - - - - - - - - - - - -1

Substituting L = W + 12 into equation 1, it becomes

W + W + 12 = 22

2W + 12 = 22

2W = 22 - 12 = 10

W = 10/2

W = 5

the equation cos(35) =a/25 can be used to find the length of bc what is the length of bc? round to the nearest tenth

step-by-step explanation:

d) by the cross product property, ab^2 = bc multiplied by ad

step-by-step explanation:

we are given

in the given triangle abc

angle a is 90° and segment ad is perpendicular to segment bc

we can see that

triangle(abc) and triangle(abd) are similar because they have common side and same angle (90 degree)

so, triangles(abc) and abd are similar

since, they are similar

so, the ratio of their sides must be equal

we get

now, we can cross multiply

and we get

so, this could be step to prove it