If you were to roll the dice one time what is the probability of it landing on an odd number?

1/2

Step-by-step explanation:

a dice has six sides and the highest number is 6

the dice should have the numbers

1,2,3,4,5,6

which 1,3,5 are odd numbers so it's a 1/2

the number of possible outcomes that do not show a 1 on the first spinner and show the number 4 on the second spinner is 2.

spinner 1 spinner 2

1                     1

1                     2

1                     3

1                     4

2                   1

2                   2

2                   3

2                   4   = not 1, and 4

3                   1

3                   2

3                   3

3                   4 = not 1, and 4

only 2 outcomes have passed the given condition.

step-by-step explanation: