Jim needs to rent a car. A rental company charges $21.0 per day to rent a car. and $0.10 for every mile driven. He will travel 250 miles. He has $115.00 to spend. Write an inequality that can be used to determine d, the maximum number of days that Jim can rent a car. Jim believes the maximum whole number of days he can rent the car is 5. Is he correct?

Yes, Jim is correct.

Step-by-step explanation:

Let d represent the number of days that Jim can rent the car.

rental company charges $21.0 per day to rent a car. and $0.10 for every mile driven. This means that if he rents the car for d days and drives x miles, the total amount that he would pay is

21d + 0.01x

He will travel 250 miles. He has $115.00 to spend. Therefore, the inequality that can be used to determine d, the maximum number of days that Jim can rent a car would be

21d + 0.01 × 250 ≤ 115

21d + 2.5 ≤ 115

21d ≤ 115 - 2.5

21d ≤ 112.5

21d ≤ 112.5/21

d ≤ 5.35

Therefore, Jim is correct

He cant rent the car for 5 days

Step-by-step explanation:

21 * 5 = 105

0.10 * 250 = 25

105 + 25 = 130

He only has 115 to spend

let's add {f(x)=x+1}f(x)=x+1 and {g(x)=2x}g(x)=2x together to make a new function.

f(x)+g(x) =(x+1)+(2x)=x+1+2x=3x+1

let's call this new function hh. so we have:

{h(x)}={f(x)}+{g(x)}{=3x+1}h(x)=f(x)+g(x)=3x+1

we can also evaluate combined functions for particular inputs. let's evaluate function hh above for x=2x=2. below are two ways of doing this.

method 1: substitute x=2x=2 into the combined function hh.

h(x)

h(2)

​    

=3x+1

=3(2)+1

=7

​ since h(x)=f(x)+g(x)h(x)=f(x)+g(x), we can also find h(2)h(2) by finding f(2) +g(2)f(2)+g(2).

first, let's find f(2)f(2):

f(x)

f(2)

​    

=x+1

=2+1

=3

​  

now, let's find g(2)g(2):

g(x)

g(2)

​    

=2x

=2⋅2

=4

​  

so f(2)+g(2)=3+4=\greend7f(2)+g(2)=3+4=7.

notice that substituting x =2x=2 directly into function hh and finding f(2) + g(2)f(2)+g(2) gave us the same answer!

i'm a sophomore in connections, i'd recommend checking on jishka.com they have a large range of questions and answers from our school.