Imagine that the average weight of a total of 500 girls in a high school is 35kg. Tom randomly sampled 10 girls and measured their weight. And then he repeated this procedure for three times. The means and standard deviations are listed as following. Which sample estimate shows the least sample variability?

The sample 2 has a lowest value of SE corresponding to the least sample variability.

Step-by-step explanation:

As the value of the sample means and standard deviations are not given, as similar question is found online from which the values of data is follows

The data is as attached with the solution. From this data

Sample 1 has a mean of 34 and a SE of 5

Sample 2 has a mean of 30 and a SE of 2

Sample 3 has a mean of 26 and a SE of 3

Sample 4 has a mean of 38 and a SE of 5

As per the measure of the sample variability is linked with the value of SE or standard error. Which is lowest in the case of sample 2 .

So the sample 2 has a lowest value of SE corresponding to the least sample variability.

x =±sqrt(1/3)

step-by-step explanation:

x+4/6x=1/x

multiply each side by 6x to get rid of the fractions

6x*(x+4/6x)=1/x*6x

distribute

6x^2 +4 = 6

subtract 4 from each side

6x^2 +4-4 = 6-4

6x^2 =2

divide by 6

6x^2/6 = 2/6

x^2 = 1/3

take the square root of each side

sqrt(x^2) = ±sqrt(1/3)

x =±sqrt(1/3)

$79500

step-by-step explanation: