Consider randomly selecting a student at a large university, and let A be the event that the selected student has a Visa card and B be the analogous event for MasterCard. Suppose that P(A) = 0.6 and P(B) = 0.3.
a. What is the probability that the selected student has neither type of card?b. Describe in terms of A and B the event that the select student has a visa card, but not a mastercard? and then calulate the probability of this event. c. Calcuate th probability that the selected student has exactly one of the two types of cards?

a) Therefore, the probability is P=0.28.

b) Therefore, the probability is P=0.42.

c) Therefore, the probability is P=0.54.

Step-by-step explanation:

We know that A be the event that the selected student has a Visa card and B be the analogous event for MasterCard. Suppose that:

P(A) = 0.6 and P(B) = 0.3.

a) We calculate the probability that the selected student has neither type of card:

Therefore, the probability is P=0.28.

b) We calculate the probability that the select student has a visa card, but not a mastercard:

Therefore, the probability is P=0.42.

c) We calculate the probability  that the selected student has exactly one of the two types of cards:

Therefore, the probability is P=0.54.

$53.50

step-by-step explanation:

you have to subtract the amount of money chuck earned ($72.50) by the cost of the gas for the mower ($11.25) and the new string for the trimmer he bought ($7.75).

72.50-11.25=61.25

and then subtract $61.25 by the second thing he bought (the new string for the trimmer)

61.25-7.75=53.5

so in total it's $53.50 (53 dollars and 50 cents)

b

step-by-step explanation: