31.6 An older proof of Theorem 31.3 goes as follows, which we outline for c = 0. Assume x > 0, let M be as in the proof of Theorem 31.3, and let F(t) = f(t) + n −1 k=1 (x − t)k k! f(k) (t) + M · (x − t)n n! for t in [0, x]. Show F is differentiable on [0, x] and F (t) = (x − t)n−1 (n − 1)! [f(n) (t) − M].

is there a picture

step-by-step explanation:

the answer is a

step-by-step explanation:

3

step-by-step explanation:

in standard form:

a= dictionaries

b= maps

you have to buy 3 dictionaries, so put a 3 next to the a (dictionaries) so that you can multiply them by each other.

a3+b= 60 (the amount of money you have)

we already know the cost of a=15 so replace a with $15

($15 x 3)+b=60

multiply 15 and 3 to get $45 and replace it with $45

45+b=60

and then replace b with 15 to get the total:

45+15=60

that means you have $15 left after buying 3 dictionaries.

15 divided by the cost of a map ($5) equals 3.

so you can buy 3 maps.

sorry if it was confusing!