A random sample of 250 working adults found that 74% access the Internet at work, 88% access the Internet at home, and 72% access the Internet at both work and home. Find the probability that a person in this sample selected at random accesses the Internet at home or at work.

The answer to the question is

The probability is 0.9 or 90 %

Step-by-step explanation:

To solve the question, we note that

Number of population sampled = 250

Percentage that access the internet at work = 74 % = P(A)

The number that  access the internet at home = 88% while = P(B)

The number that  access the internet at home and at work = 72 % hence =P(C)

The probability that a person in this sample selected at random accesses the Internet at home or at work is given by P(A) U P(B) - P(AnB)

Which gives 0.74+0.88-0.72 = 0.9 or 90 %

answer: a and c are correct

step-by-step explanation:

the +5 is the vertical translation

the added negative symbol in front is the reflection over the y-axis

answer: options?

step-by-step explanation: