A colony of bacteria is growing at a rate of 0.2 times its mass. Here time is measured in hours and mass in grams. The mass of the bacteria is growing at a rate of 4 grams per hour after 3 hours.

a. Write down the differential equation the mass of the bacteria, m, satisfies:
b. Find the general solution of this equation. Use A as a constant of integration.
c. Which particular solution matches the additional information? m(t) =
d. What was the mass of the bacteria at time t=0? mass =

a) dm/dt = 0.2m

b) ln(m) = 0.2t + A

c) ln(m) = 0.2t + ln(20) - 0.6

d) 11 grams

Step-by-step explanation:

a) dm/dt = 0.2m

b) dm/m = 0.2dt

ln(m) = 0.2t + A

c) At t = 3, dm/dt = 4

dm/dt = 0.2m

4 = 0.2m

m = 4/0.2 = 20

So, when t = 3, m = 20

ln(20) =0.2(3) + A

A = ln(20) - 0.6

ln(m) = 0.2t + ln(20) - 0.6

d) find m when t=0

ln(m) = 0.2(0) + ln(20) - 0.6

ln(m) = ln(20) - 0.6

ln(m) = 2.3957322736

m = e^2.3957322736

m = 10.9762327224

m = 11

answer:

it is general formula that is used to write value to its excet position

a11 a12 a13

a21 a22 a23

it is the example of order 2 by 3 matrix in this

a11 means value occur in 1 st row 1st column

a12 means value occurs in 1st row 2nd column

a13 means value occur in 1st row and 3rd column

a21 means value occurs in 2nd row and 1st column

a22 means value occurs in 2nd row and in 2nd column

a23 means value occurs in 2nd row and in 3rd column