A cylinder has radius 1.6 meters. it’s volume is 95 cubic meters. what’s the height to the nearest tenth of a meter?

Solution:

The volume of cylinder is given as:

Where,

r is the radius and h is the height of cylinder

From given,

V = 95 cubic meters

r = 1.6 meters

h = ?

Substituting the values we get,

Thus height of cylinder is 11.8 meters

option 2 is correct.

step-by-step explanation:

we are given two inequality equation

x+y> 5 and -3x+2y< -2

first we draw the graph of both function using t-table method

equation: x+y> 5

for x=0, y=5

for x=-5, y=0

table:

x   :   0     5

y   :   5     0

test point (0,0) , 0> 5

false

equation: -3x+2y< -2

for x=0, y=-1

for x=2, y=4

table:

x   :   0     2

y   : -1       4

test point (0,0) , 0< -2

true

now we draw the graph. see the attachment for graph.

common region would be solution set.

option 2 is correct.