Mathematics, 21.02.2020 05:31 kloyet11
A distribution of scores for a test of life stressors has a mean of µ = 125 and standard deviation of σ = 15. The researcher calculates z-scores to standardize the distribution. What are the mean and the standard deviation for the z-scores in this distribution?
Answers: 1
![E(z)=E[\frac{x-\mu}{\sigma} ]=\frac{1}{\sigma}\times [E(x)-\mu] =\frac{1}{\sigma}\times [\mu-\mu]=0](/tpl/images/0518/9631/1ce11.png)
![Var(z)=Var[\frac{x-\mu}{\sigma} ]=\frac{1}{\sigma^{2}}\times [Var(x)-Var(\mu)] =\frac{\sigma^{2}-0}{\sigma^{2}}=1\\SD(z)=\sqrt{Var(z)}=1](/tpl/images/0518/9631/0033d.png)
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A distribution of scores for a test of life stressors has a mean of µ = 125 and standard deviation o...
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