Four mathematics books and seven history books are arranged on a bookshelf in how many of the possible arrangements are no two mathematics books next to each other?

120

Step-by-step explanation:

No of math books = 4

No of History books = 7

Since no two math books are next to each other, we can say each math book is sandwiched between two history books like

H⇔M⇔H

We can assume that this there books in system above is binded together, thus we will have

3 binded combinations  H⇔M⇔H

1  single Math book                M

1 single History book              H

No of possible arrangements = (3+1+1)! =5! = 5 x 4 x 3 x 2 x 1 = 120

the answer is a

step-by-step explanation:

(a) the volume of the cone is 20/3 in3

hence, option a is correct.