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Mathematics, 21.02.2020 01:24 priscilalegarda

H(1)=9
h(2)=3
h(n)=h(nβˆ’2)β‹…h(nβˆ’1)
what is h(3)

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Answers: 3

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H(1)=9
h(2)=3
h(n)=h(nβˆ’2)β‹…h(nβˆ’1)
what is h(3)...
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