You flip a fair coin 10,000 times. Approximate the probability thatthe difference between the number of heads and the number of tails is at most 100.

E[X] = (np) (p+(1-p))^(n-1)

With n =10,000 and p=0.50 we get

E[X]= (10,000*0.50) (0.50+(1–0.50))^(10,000–1)

E[X] = 5,000(1)

So assuming the coin is fair (p=50%), then we can expect to get heads 5,000 times when the coin is tossed 10,000 times.

Step-by-step explanation:

answer: bearing in mind that a rectangle has a perimeter of length + length + width + width.

step-by-step explanation:

p = perimeter

l = length

x=width

p = 2l + 2x

p = 2(l+x)     < ==== perimeter of the base of the box.