Find the coordinates of the vertices of the figure after the given transformation. reflection across the x-axis A) U'(0, 5), P'(-1, 0), R'(3, -1), D'(3, 2) B) U'(2, -4), P'(1, 1), R'(5, 2), D'(5, -1) C) U'(-1, 3), P'(-2, 2), R'(2, 3), D'(2, 0) D) U'(-4, -3), P'(-5, 2), R'(-1, 3), D'(-1, 0)

well the 1 and -1 are always after the 0 and the 0 is inthe middle. s thats what i would guess. but i dont know what a slope of 2 is sorry

step-by-step explanation:

u = -(6/7)w

step-by-step explanation:

place all values with 'u' on one side of the equation.

4u + 8w = - 3u + 2w

4u + 3u = 2w - 8w

further simplify the equation by solving the addition and subtraction.

7u = - 6w

make 'u' the independent variable by placing its co-efficient on the right-hand side.

u = - (6/7)w

y=3x+4

step-by-step explanation:

given the points a(0,4) and b(-4, -8)

eqn of line ab: (y-4)/(x-0)=(-8-4)/(-4-0)

(y-4)/x=-12/-4=3

y=3x+4