How do you solve this equation 27s-29=54s-83

s=2

Step-by-step explanation:

27s-29=54s-83

you want to get each variable on each side, so s on one side of the equal sign and the no variable on the other, but you can just put them there you can to add and subtract a variable of each side of them to get 0.

step 1.) 27s(-54s)-29=54s(-54s)-83

now you have -27s-29=-83, that's half of the equation done

step 2.) -27s-29(+29)=-83(+29)

you addition on this one because the even though it is a subtraction problem a - is always a negative number (think of it as adding a negative number)

you now have -27s=-54

step 3.) -27s/-27=-54/-27

at the end you (usually) always want the variable to be by itself so in this case s and on the left side. the answer is s=2

check.) you can check problems like this by substituting the variable for the number, so here is the check;

27x2-29=54x2-83

54-29=108-83

25=25

25 is the same as 25 which means that 2 is the correct answer

hello from mrbilldoesmath!

answer:

25x^2 + 90x + 84

discussion:

mn(x) = m(n(x)) = m( 5x + 9) =

(5x + 9)^2 + 3 =>

25x^2 + 90x + 9^2 + 3 =

25x^2 + 90x + 84                 (as 9^2 = 9*9 = 81)

which is the second choice

regards,  

mrb

p.s.   i'll be on vacation from friday, dec 22 to jan 2, 2019. have a great new year!

u = -(6/7)w

step-by-step explanation:

place all values with 'u' on one side of the equation.

4u + 8w = - 3u + 2w

4u + 3u = 2w - 8w

further simplify the equation by solving the addition and subtraction.

7u = - 6w

make 'u' the independent variable by placing its co-efficient on the right-hand side.

u = - (6/7)w