Use calculus to find the volume of the following solid S S : The base of S is a circular disk with radius r. Parallel cross-sections perpendicular to the base are isosceles triangles with height and unequal side in the base.

The correct answer is: A = 1/2 bh V = integral A(x) from [-r, r].

Step-by-step explanation:

x^2 +y^2 = r^2 A = 1/2 bh b = 2y = 2sqrt[r^2 - x^2] so that gives A = 1/2 [ 2sqrt(r^2 - x^2)]h which gives A = sqrt[r^2 - x^2]h

just do 5.2 + 2 ( 7.2) and 1/3 x 3 (.9) and youv'e got your equation. 0.9( 9/10) + 7.2 ^2 = 16.4 hope i could !

step-by-step explanation: