The John Deere company has found that the revenue from sales of heavy-duty tractors is a function of the unit price p it charges. If the revenue R is:

R=-1/2p^2+1900p

What unit p should be charged to maximize revenue?
What is the maximum revenue?

1900 unit p should be charged to maximise revenue and 1805000  is the maximum revenue

Step-by-step explanation:

The equation represents a parabola that is looking down and has the maximum, we have to find the vertex of equation.(p,R)

vertex =  

Here b = 1900

a =

On substituting the values

  it is your x for vertex

put it in your equation and calculate:

= -1805000 + 3610000= 1805000

price must be equal 1900 to maximise the revenue = 1805000

6/20

step-by-step explanation: