The figure below shows a shaded rectangular region inside a large rectangle:

A rectangle of length 10 units and width 5 units is shown. Inside this rectangle is a smaller rectangle of length 4 units and width 2 units placed symmetrically inside the larger rectangle. The smaller rectangle is shaded gray.

What is the probability that a point chosen inside the large rectangle is not in the shaded region?

8%
16%
50%
84%

Step-by-step explanation:

The formula for determining the length of a rectangle is expressed as

Area = length × width

The large rectangle has a length of 10 units and width 5 units. The area of the large rectangle would be

10 × 5 = 50 units²

Inside this rectangle is a smaller rectangle of length 4 units and width 2 units. The area of the smaller rectangle would be

4 × 2 = 8 units²

Probability is expressed as favorable outcome/total number of possible outcomes

The region that is not shaded grey is

50 - 8 = 42 units²

The probability that a point chosen inside the large rectangle is not in the shaded region is

42/50 = 0.84

Converting to percentage, it becomes

0.84 × 100 = 84%

i need more information

step-by-step explanation:

9 x 8 divided by (5-3)=36