2 The test statistic in a two-tailed test is z=-2.75 use a 0.05 significance level to find the P value and state the conclusion about the null hypothesis

The p-value of the test statistic is p-value = 0.006.

The null hypothesis will be rejected at 5% level of significance.

Step-by-step explanation:

The hypothesis is two-tailed.

The test statistic value is: z = -2.75.

The significance level of the test is: α = 0.05.

The p-value of a two-tailed test is:

**Use the z-table for the probability.

The p-value of the test statistic is p-value = 0.006.

The decision rule for a hypothesis test based on p-value is:

If the p-value is less than the significance level the null hypothesis is rejected and vice-versa.

The p-value = 0.006 < α = 0.05.

Thus, the null hypothesis will be rejected at 5% level of significance.

too hard the other guy did it

step-by-step explanation:

150.6

all i did was i multiplied 5.02 by 30