A 0.45-mm-wide slit is illuminated by light of wavelength 590 nm. What is the width (in mm) of the central maximum on a screen 1.5 m behind the slit?

And if we convert this into mm we got:

Step-by-step explanation:

For this case we have the following info givenL

represent the wavelength

represent the width of the single slit

represent the longitude

And we want to find the maximum width of the central maximum in mm, so we can use the following formula:

And if we solve for w the width we got:

And replacing we got:

And if we convert this into mm we got:

(- 1, 0 )

step-by-step explanation:

an x- intercept is where the function crosses the x- axis.

to find the x- intercept/s look for the value of x when f(x) = 0

from the given table there are 3 values of x where f(x) = 0

when x = - 1, x = 2, x = 3

the one that is listed is (- 1, 0 )