While visiting a friend's home, i saw kittens and children playing in the backyard. counting heads, i got 11. counting feet, i got 32. how many kittens and how many children were in the backyard?

There are 5 cats and 6 children

Step-by-step explanation:

Let x = number of cats

Let y= number of children

Counting heads gives 11

X+Y = 11 eq1

Counting feet gives 32

Cats has 4legs,child has 2 legs

4X + 2Y=32 eq2

X = 11 - Y

Put in eq2

4(11-Y) + 2Y = 32

44 - 4Y + 2Y=32

12=2Y

Y=12/2=6

Y=6= Children

Put Y=6 in eq2

X + 6=11

X=11-6=5

X= 5 = cats

yes. we do proportions in probabilities.

.24

step-by-step explanation:

the probability is   .24

the first player had the highest probability of getting a silver marble

the game could be made fair by adding back the marble that was drawn after each draw