What is the average rate of change for h(t) between t=0 and t=2
The height of the ball is _ for 0

Part a: Option D 18 feet per second

Part b: increasing

Solution:

Height

Part a: To find the average rate of change for h(t) between t = 0 and t = 2.

Substitute t = 0 in h(t).

h(0) = 3

Substitute t = 2 in h(t).

h(2) = 39

Average rate of change formula:

Here, a = 0 and b = 2.

           = 18

Average rate of change = 18 feet per second

Option D is the correct answer.

Part b:

This means height of the ball is increasing for 0 < x < 2.

x=-7

step-by-step explanation:

x+3=-10

-10+3=-7

x=-7