What is the probability that the second die will have "" a number that is less than the number on the first die ""? (4 points)

5/12.

Step-by-step explanation:

The possible outcomes  when second die is less than the first are as follows:

6 and a number < 6 -  5 outcomes.

5  and a number < 5 - 4 outcomes.

4 and < 4 - 3 outcomes.

3 and < 3 - 2 outcomes.

2 and a 1 - 1 outcome.

Total of these =  15 outcomes.

The sample space ( that is the number of all possible outcomes) = 6*6 = 36.

So the required probability = 15/36

= 5/12.

squares, rhombus, rectangles

in simplified version   it would be x ≤-4

step-by-step explanation:

multiply each term in x ≤-4 by -1