Find a parametrization of the ellipse centered at the origin in the xy-plane that has major diameter 12 along the x-axis, minor diameter 8 along the y-axis, and is oriented counter-clockwise. Use t as the parameter. It should change from 0 to 2*pi. Your parametrization should make the point (6,0) correspond to t = 0.
x(t) =
y(t) =
(0 <= t <= 2*pi).

x = 6 cos t

y = 6 sin t

where t varies from 0 to 2pi

Step-by-step explanation:

Given that an ellipse is centred at the origin in xy plane.

So equation would be of the form

Major axis =2a= 12

so a=6

Minor diameter = 8

b = 8/2 = 4

a=6 and b =4

Also (6,0) should correspond to t=0

So best parametrization would be

x = 6 cos t

y = 6 sin t

where t varies from 0 to 2pi

logv3(x+2)=1

rewrite in exponential form:

logb(x) = y is equal to b^y =x

b = 3, y = 1

now solve for x:

3^1 = x+2)

x = 3-2

x = 1

see the picture for the graph.