Determine whether the set, together with the standard operations. is a vector space. If it is not. Identity at least one of the ten vector space axioms that fails. The set of all quadratic functions whose graphs pass through the origin. 1) The set {(x, 1/2 x): x is a real number} 2) The set of all 2 x 2 matrices of the form [a c b 0] 3) The set of all 2 X 2 matrices of the form [a c b 1] 4) The set of all 4 x 4 matrices of the form [0 a a a a 0 b b b b 0 c c c c 0] 5) The set of all 3 X 3 upper triangular matrices. C[-1, 1]. 6) The set of all continuous functions defined on the interval [-1, 1]. Let V be the set of all positive real numbers.

step-by-step explanation:

we are given a graph for system of inequalities.

in order to write the system of inequalities for the given graph, we need to find the inequality for each of the line separately.

let us find the slope of dotted line first.

taking two coordinates on the graph.

let us say (0,0) and (3,1).

let us find the slope of the line now.

slope of the dotted line would be =.

y-intercept of dotted line is y=0 only.

plugging slope m= and b=0 in slope-intercept form y=mx+b, we get

.

the line is shaded up of that dotted line.

therefore, for shading up we would take greater than inequality symbol > .

and because it's a dotted line we would take only > symbol in place of = sign in above equation of line.

therefore, inequality for dotted line would be

let us take two points (3,1) and (0,4) on the solid line.

slope of the solid line would be =.

for the solid line we have y-intercept b= 4.

plugging slope m= -1 and b=4 in slope-intercept form y=mx+b, we get

y = -1x + 4.

the line is shaded down of that solid line.

therefore, for shading down we would take less than inequality symbol < .

and because it's a solid line we would take ≤ symbol in place of = sign in above equation of line.

therefore, inequality for solid line would be

idk

step-by-step explanation:

well what you have to do is divide 84 by 6 so theanswer

step-by-step explanation:

84 divided by 6 = 14

and that lightbulb changing party must be freaking lit!

or

step-by-step explanation:

we need to solve for 'x' the following equation:  

we have that:

⇒

⇒ ⇒

factorizing, we get that:

  ⇒

then, the solutions are: or

nothing extraneous has been found!