Write an equation for the line parallel to the line −4x−8=0 through the point (0,−9)

4y= -x - 28

Step-by-step explanation:

the products of the gradient of parallel lines is 1

m1 x m2=1(1)

8-4x=0

re-arranging we have

0=-4x +8

comparing with y=mx +c we have

m1=-4

put the value of m1 in eqn 1

-4 xm2 =1

m2 =-1\2

from the relation

m=y-y1\x-x1

put the value of m1 above

-1\2=y-(-9)\x-0

cross multiply

-1(x-8)=4(y+9)

-x +8=4y+36

re-arranging we have

4y=-x-36+8

4y=-x-28//

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