A pizza chain wants to send codes for $2 off a large pizza to the subscribers of its e-mail list. Each coupon code will have three letters followed by two digits. The letters M, N, and O and the digits 1, 3, 5, and 7will not be used. So, there are 23 letters and 6 digits that will be used. Assume that the letters and digits can be repeated. How many such coupon codes can be generated?

438,012 ways.

Step-by-step explanation:

We have been given that each coupon code will have three letters followed by two digits. The letters M, N, and O and the digits 1, 3, 5, and 7 will not be used. So, there are 23 letters and 6 digits that will be used.

Since the letters and digits can be repeated, so we will use fundamental principal of counting.

For first place, we can use 23 letters, for 2nd and 3rd place we can use 23 letters.

We can use 6 digits for 1st digit place and 6 digit for 2nd digit place as repetition is allowed.

So we can choose coupon code is following ways:

Therefore, we can choose coupon codes in 438,012 ways.

24/56=hx^7

step-by-step explanation:

answer:   b

step-by-step explanation:

x2 = 16

x can not be a negative number because 16 is positive

the only answer would be positive 8