A triangle has sides with lengths of 60 millimeters, 82 millimeters, and 100 millimeters. Is it a right triangle?
Yes or No

No

Step-by-step explanation:

Pythagorean Theorem

60 x 60 = 3600

82 x 82 = 6724

6724 + 3600 = 10324, not 10000 (100 squared)

So it isn't a right triangle

No

Step-by-step explanation:

Longest side of the triangle has the length = 100 mm

Other two sides are 60 mm and 82 mm

If the triangle is a right triangle then square of the longest side is equal to the sum of squares of the other two sides.

Left Hand Side = = 10000

Right Hand Side =

=

=

So the left hand side is not equal to right hand side. The condition for right triangle is NOT satisfied.

the first question mark is 6 and the second question mark is 26 (the square root)

step-by-step explanation:

the correct functions are

h(x) = 3x + 2  

g(x) = 2^x

step-by-step explanation:

i proceed to calculate the different values ​​of k (x)

case 1)  k(x) = g(x) ∘ h(x)

g(x) ∘ h(x)=g(h(x))

k(x) = [2]^[3x + > is the option  4. k(x) = 2^(3x + 2 )

case 2)  k(x) = g(x) + h(x)

k(x) = [2^x]+[3x + 2]=2^x+3x+> is the option  1.) k(x) = 2^x + 3x + 2

case 3)k(x) = h(x) ÷ g(x)

k(x) =  [3x + 2]/[2^x]=3x/(2^x)+2/(2^x)=3x*(2^-x)+2^(1-x)

is the option  3.)   k(x) = (3x)2^(-x) + 2^(-x + 1 )

case 4)k(x) = g(x) - h(x)

k(x) =  [2^x]-[3x + 2]=2^x-3x-> is the option  2.) k(x) = 2^x - 3x - 2 

case 5)  k(x) = g(x) × h(x)

k(x) = [2^x]*[3x + > is the option  5.) k(x) = 2^x(3x + 2)

case 6)k(x) = h(x) ∘ g(x)

h(x) ∘ g(x)=h(g(x))

k(x)=3*[2^x]+> is the option  6. k(x) = 3(2^x) +2