Five fair dice were tossed, and the sum of the resulting tosses was recorded. This process was repeated 4,000 times using a computer simulation. The number of times the sum of the five tosses equaled 28 was 43. What is the estimated probability that the sum of the five dice will be 28? (Give the answer to four decimal places.)

The estimated probability that the sum of five dice will be 28 is 0.0108

Step-by-step explanation:

Given.

N = Number of Repeated Process = 4,000

n = Number of times the sum of the five tosses equaled 28 = 43

The estimated probability that the sum of the five dice will be 28 = n/N

Where n = 43

And N = 4,000

Using the above formula, we have the following:-

n/N becomes

n/N = 43/4000

n/N = 0.01075

n/N = 0.0108 Approximated to 4 decimal w

Hence, the estimated probability that the sum of five dice will be 28 is 0.0108

answer: 21$

step-by-step explanation:

$42 / $14 = 3   (ratio 3: 1)

$7 x 3 = $21

b

step-by-step explanation: